1.

An electric kettle of 2kWfor 2h daily. Calculate the (i) energy consumed in SI and commerical unit, (ii) cost of running it the month of June at the rate of Rs 3.00 per unit?

Answer»

Solution :Here Power P=2kW time of use t=2h DAILY
`therefore` Total time of use in the MONTH of June `t=2 times 30=60h`
`therefore` (i) Energy CONSUMED `E=P times t=2kW times 60h=120k Wh=120 units`
`implies E=120 times 3.6 times 10^6 J=4.32 times 10^8 J`
(ii) COST @ Rs 3.00 per unit `=3 times 120= 360`


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