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An electron of mass m and charge q is travelling with a speed v along a circular path of radius r atright angles to a unifom of magnetic field B.If speed of the electron is doubled and the magneliofield is halved, then resulting path would have a radius of(A) r/4(C) 2r(B) r/2(D) 4r |
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Answer» R =mv/qB since speed of the electron is doubled and the magnetic field is halved so R =4r |
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