1.

An electronic bulb drow 2.5 A current at 10v find the resistance of the filament of bulb

Answer»

\checkmark Given:

An electronic bulb draws 2.5 A current at 10 V

\checkmark To Find:

The resistance of the filament of bulb

\checkmark Solution:

We KNOW that,

\dagger Ohm's LAW:

\red{\bigstar \ \boxed{\rm V=IR}}

Here,

  • V = voltage
  • I = current
  • R = resistance

\star Units:

  • V = Voltage (V)
  • I = Ampere (A)
  • R = Ohm (Ω)

According to the question,

We are asked to find the resistance of the filament of bulb

So, we MUST find "R"

Therefore,

\orange{\bigstar \ \boxed{\rm R=\dfrac{V}{I}}}

Given that,

An electronic bulb draws 2.5 A current at 10 V

HENCE,

  • V = 10 V
  • I = 2.5 A

By substituting the values,

We get,

\blue{\implies \rm R=\dfrac{10}{2.5} \ \Omega}

On further simplification,

We get,

\green{\implies \rm R=4 \ \Omega}

Hence,

\pink{\bigstar \ \boxed{\rm Resistance \ (R)=4 \ \Omega}}

Therefore,

The resistance of the filament of bulb = 4 Ω



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