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An element 'M' with electronic configuration (2, 8, 2) combines separately with (NO_(3))^(-), (SO_(4))^(2-) and (PO_(4))^(3-) radicals. Write the formula of the three compounds so formed. To which group and period of the Modem Periodic Table does the element 'M' belong ? Will 'M' form covalent or ionic compounds ? Give reason to justify your answer. |
Answer» SOLUTION :The element M has 2 electrons in the last orbit. Thus it FORMS `M^(2+)` or it has a VALENCY of `+2`. ![]() The element M belongs to Group 2 and period 3 of the Modem Periodic Table. The element M will form IONIC COMPOUNDS. It has a tendency to lose 2 electrons to gain stable octet configuration. Thus it will form ionic bonds and give rise to ionic compounds. |
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