1.

An elevator and its load have a total mass of 800 kg. If the elevator, originally moving downwards at `10 ms^(-1)`, is brought to rest with constant deceleration in a distance of 25 m, the tension in the supporting canble will be (`g=10 ms^(-2)`)A. 8000 NB. 6400 NC. 11200 ND. 9600 N

Answer» Correct Answer - D
(d) Given, `u=10 ms^(-1),v=0`,
So using, `v^(2)=u^(2)-2as`
`0=(10)^(2)-2(a)(25)`
`therefore a=2 ms^(-2)` (upwards)
Now, `T-800g=800a`
`therefore T=800(10+2)=9600 N`


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