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An elevator car whose floor to ceiling distance is equal to `2.7 m` starts ascendiung with constant acceleration `1.2(m)/(s^(2))`, 2 sec after the start a bolt begins falling from the ceiling of the car. Answer the following question `g=9.8 m//s^(2)` Distance covered by the bolt during the free fall time w.r.t. ground frame.A. 0.7 mB. 0.9 mC. 1.1 mD. 1.3 m |
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Answer» Correct Answer - D Distance `s|Deltaty|+(2u^(2))/(2g)=0.7+((2.4)^(2))/(9.8)=1.3m` |
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