InterviewSolution
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InterviewSolution
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An elevator is descending with uniform acceleration.To measure the acceleration, a person in the elevator drops a coin at momen the elevator strts. The coin is 6 ft asbove the floor of the elevator at the time it is dropped. The person observes that the coin strikes the floor in 1 second. Calculate these dta the acceleration of the elevator. |
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Answer» Correct Answer - B::D For elevator and coin u=0 as the elevator descends down ward with acceleratiion a (say) the coin has to move more distance than 1.8 cm to strike the floor. Time takes t=1 sec `S_e=ut+ 1/2 at^2 =0+ 1/2 g(1)^2=1/2 g`, S_3 = ut+ 1/2 a`t^2` = 0+ 1/2 a`(1)^2`= 1/2 a `` Total distance covered by coin given by `1.8+1/2 a= 1/2 g rarr 1.8 + a/2= 9.8/2=4.9 rarr a/2= 4.9=1.8=3.1m rarr a= 6.2 m/s^2 = 6.2xx3.28=20.34 ft/s^2`. |
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