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An elevator is moving up with an acceleration g/5.The apparent weight of a 60 kg man standing in the lift isTake [g =10 ms^-2](A) 480 N(B) 720 N(C) 600 N(D) 1000 N |
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Answer» Due to movement of elevator , the pseudo force will act downward along with Mg soz the net force will be = mg +mg/5 = 6mg/5 = 720N option B |
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