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An elevator starts from rest with a constant downward acceleration and covers `2.5m` in first second If the lift weighs `200kg` what would be the tension in the ropes of the lift ? |
Answer» Correct Answer - `960N` . Here, `u =0, s = 2.5 m, t = 1 s, m t =1 s, m =200 kg` `R=`? `s = ut + (1)/(2) at^(2) = (1)/(2)at^(2)` `a = (2s)/(t^(2)) =(2xx2.5)/(1^(2)) =5 m//s^(2)` `R =m (g -a) = 200 (9.8 -5)` `=960N` . |
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