

InterviewSolution
Saved Bookmarks
1. |
An elevator weighs `4000kg` When the upward tension in the supporting cable is `48000 N` what is the upward acceleration? Starting from rest, how far does it rise in `3` seconds ? |
Answer» Correct Answer - `2.2 ms^(-2) ; 9.9m` . Here, `m = 400kg, T = 48000 N a = ?` As `T =m (g +a)` `:. g + a = (T)/(m) = (48000)/(4000) = 12` `a = 12 - g = 12 -9.8 = 2.2 ms^(-2)` (ii) `u = 0, s = ? T = 3 sec` From `s = ut + (1)/(2)at^(2) = 0 + (1)/(2) xx2.2 xx3^(2) = 9.9m` . |
|