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An engine of `100H.P` draws a train of mass `100` metic ton with a velocity of `36km h^(-1)` Find the coefficient of friction. |
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Answer» Correct Answer - `0.0076` Here `P = 100 HP = 100 xx 746 "watt"` `upsilon =36km h^(-1) = 10ms^(-1)` If `F` is frictional force overcome by the engine then `P = F xx upsilon F = (P)/(upsilon) = (100 xx 746)/(10) = 7460 N` `R = mg = 100 xx 1000 xx 9.8 N = 9.8 xx 10^(5)` `mu = (F)/(R) = (7460)/(9.8 xx 10^(5)) = 0.0076` . |
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