An equi – convex lens of glass, refractive index 1.5 has focal lengt

1.	An equi – convex lens of glass, refractive index 1.5 has focal length 0.4 m in air. Calculate the focal length of the lens when is immersed in a liquid of refractive index 1.7. What is the nature of the lens in the liquid?Can someone plz give me the explanation as well?
Answer» Answer: Correct option is B 8 15 Given, μ 1 =1.5 F 1 =0.2m f 2 =(−0.5) μ 2 =? Using LENS MAKERS formula and taking RATIOS, f 2 f 1 = (μ 1 −1) (μ 2 −1) ⇒ (−0.5) 0.2 = (1.5−1) ( μ e 1.5 −1) ⇒ 0.5 0.2×0.5 =(1− μ e 1.5 ) ⇒ μ e 1.5 =0.8 ⇒μ e = 8 15

An equi – convex lens of glass, refractive index 1.5 has focal length 0.4 m in air. Calculate the focal length of the lens when is immersed in a liquid of refractive index 1.7. What is the nature of the lens in the liquid?Can someone plz give me the explanation as well?

Answer»

Answer:

Correct option is

Given,

=1.5

=0.2m

=(−0.5)

Using LENS MAKERS formula and taking RATIOS,

(μ

−1)

(μ

−1)

⇒

(−0.5)

0.2

(1.5−1)

(

1.5

−1)

⇒

0.5

0.2×0.5

=(1−

1.5

)

⇒

1.5

=0.8

⇒μ

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An equi – convex lens of glass, refractive index 1.5 has focal length 0.4 m in air. Calculate the focal length of the lens when is immersed in a liquid of refractive index 1.7. What is the nature of the lens in the liquid?Can someone plz give me the explanation as well?​

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An equi – convex lens of glass, refractive index 1.5 has focal length 0.4 m in air. Calculate the focal length of the lens when is immersed in a liquid of refractive index 1.7. What is the nature of the lens in the liquid?Can someone plz give me the explanation as well?