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An explosion blows a rock into three pieces Two pieces whose masses are 200 kg and 100 kg go off at `90^(@)` to eachother with a velocity of `8 m//s ` and ` 12 m//s ` respectively If the third piece flies off with a velocity of` 25 m//s` then calculate the mass of this piece and indicate the direction of flight of this piece in a diagram. |
Answer» Here , ` m_(1) = 200 kg , upsilon_(1) = 8 m//s ` `m_(2) = 100 kg , upsilon_(2) = 12 m//s` `upsilon_(3) 25 m//s , m_(3) = ? ` `vec(p_(1)) = m_(1) vec(upsilon_(1)) = 200 xx 8 = 1600 kg m//s` , along OB `vec(p_(2)) = m_(2) vec (upsilon_(2)) = 100 xx 12 = 1200 kg m//s` , along OA Resultant momentum of these two pieces `p = sqrt(p_(1)^(2)+ p_(2)^(2)) = sqrt((1600)^(2) + (1200)^(2)` ` = 2000 kg m//s ` If `theta` is angle made by `vec(p)` with `vec(OA)` , then `tan theta = p_(1)/(p_(2)) = (1600)/(1200) = 1.33 ` `theta = tan^(-1) (1.33) = 53^(@)` From `p = m_(3) upsilon_(3)` `m_(3) = (p)/(upsilon_(3)) = (2000)/(25) = 80 kg ` |
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