An ideal gas is at constant pressure its temperature is increased by 1

1.	An ideal gas is at constant pressure its temperature is increased by 10K then its volume increases 0.2%. Find out its initial pressure
Answer» CORRECT QUESTION - An ideal gas is at constant pressure its temperature is INCREASED by 10 K then its volume increases 0.2%. Find out its initial Temperature ♋♋YOUR ANSWERS♍♍ ✍ T = 5000 K ════════════════════ EXPLANATION — Given — Temperature increased to 10k Volume increases by 0.2 % Let initial Volume be V✔ And initial Temperature is T✔ We have ideal equation $PV = nRT$ Since pressure is constant Here R is ALSO constant Therefore Ratio will be in proportion ⇒V is proportional to T ⇒V ∝ T Final Volume = $V + \frac{0.2}{100} V \\ \\ = 1.002V$ Final Temperature $= T + 10$ ___________________________ WE HAVE V ∝ T $\frac{V}{1.002V} = \frac{T}{T + 10} \\ = > T + 10 = 1.002T \\ \\ on \: solving \\ = > T = 5000 K$ ╒══════════════════════╕ ♌ ‌ ‌‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ Thanks‌ ,hope you LIKE it !!‌ ‌ ‌‌ ‌♌ ╘══════════════════════╛

An ideal gas is at constant pressure its temperature is increased by 10K then its volume increases 0.2%. Find out its initial pressure

Answer»

CORRECT QUESTION -

An ideal gas is at constant pressure its temperature is INCREASED by 10 K then its volume increases 0.2%. Find out its initial Temperature

♋♋YOUR ANSWERS♍♍

✍ T = 5000 K

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EXPLANATION —

Given —

Temperature increased to 10k

Volume increases by 0.2 %

Let initial Volume be V✔

And initial Temperature is T✔

We have ideal equation

$PV = nRT$

Since pressure is constant

Here R is ALSO constant

Therefore Ratio will be in proportion

⇒V is proportional to T

⇒V ∝ T

Final Volume =

$V + \frac{0.2}{100} V \\ \\ = 1.002V$

Final Temperature

$= T + 10$

___________________________

WE HAVE V ∝ T

$\frac{V}{1.002V} = \frac{T}{T + 10} \\ = > T + 10 = 1.002T \\ \\ on \: solving \\ = > T = 5000 K$

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♌ ‌ ‌‌ ‌ ‌ ‌ ‌ ‌ ‌ ‌ Thanks‌ ,hope you LIKE it !!‌ ‌ ‌‌ ‌♌

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