InterviewSolution
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InterviewSolution
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An indicator is a weak acid and `pH` range of its colour is `3` to `5`. If the neutral point of the indicator lies in the centre of the `[H^(+)]` corresponding to given `pH` range, then `pH` at the equivalence point isA. `7.0`B. `4.0`C. `3.3`D. `5.0` |
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Answer» Correct Answer - C The neutral point is at the centre of the `H^(+)` ion concentration. `[H^(+]` at `(pH=3)` is `10^(-3)=100xx10^(-5)` `[H^(+)]` at `(pH=5)` is `10^(-5)` Thus, `[H^(+)]` at the centre `=(100xx10^(-5)+10^(-5))/(2)=(101xx10^(-5))/(2)` `:. pH= -log``((101xx10^(-5))/(2))=3.3` |
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