An iron block of mass 2 kg, fall from a height 10 m. After colliding with the ground it loses 25 % energy tosurroundings. Then find the temperature rise of theblock (Take sp. heat of iron 470 J/kg°C)

An iron block of mass 2 kg, fall from a height 10 m. After colliding

1.	An iron block of mass 2 kg, fall from a height 10 m. After colliding with the ground it loses 25 % energy tosurroundings. Then find the temperature rise of theblock (Take sp. heat of iron 470 J/kg°C)
Answer» 2kg=1000gramheight=10metre1m=100cm10m=100×10=1000Explanation:1000×1000/100×10-2=99898...the ANSWER is not this LET's TAKE out the 25%25/100=25to be CONTINUED....

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An iron block of mass 2 kg, fall from a height 10 m. After colliding with the ground it loses 25 % energy tosurroundings. Then find the temperature rise of theblock (Take sp. heat of iron 470 J/kg°C)​

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An iron block of mass 2 kg, fall from a height 10 m. After colliding with the ground it loses 25 % energy tosurroundings. Then find the temperature rise of theblock (Take sp. heat of iron 470 J/kg°C)