An object 15cm from cancave mirror of focal length 25cm what is the po

1.	An object 15cm from cancave mirror of focal length 25cm what is the position of the image?If the object is 2cm high . what is the height of the image
Answer» $\large\bf\underline {To \: find:-}$ We need to find the position of the IMAGE, and the HEIGHT of the image. $\huge\bf\underline{Solution:-}$ $\bf\underline{\red{Given:-}}$ ● object distance (u) = - 15cm ● Focal length (f) = - 25cm ● size of object (h) = 2cm ━━━━━━━━━━━━━━━━━━━ ▶ By using mirror Formula :- $\: \: \: \: \large\underline{ \boxed{ \red{ \bold{ \frac{1}{v} + \frac{1}{u} = \frac{1}{f} }}}}$ ➳ 1/v = 1/f - 1/u ➳ 1/v = 1/(-25) -1/(-15) ➳ 1/v = - 1/25 + 1/15 ➳ 1/v = (-3 + 5)/75 ➳ 1/v = 2/75 ➳ 2V = 75 ➳ v = 75/2 ➳ v = 37.5 cm And , $\red{\bf\:Magnification = h'/h = - v/u}$ ⪼ h'/2 = -37.5/-15 ⪼ h'/2 = 375/150 ⪼ h'/2 = 25/10 ⪼ h'/2 = 5/2 ⪼ 2H' = 10 ⪼ h' = 10/2 ⪼ h' = 5cm Hence, ▶ Image distance (v) = 37.5cm ▶ Object height (h) = 5cm ━━━━━━━━━━━━━━━━━━━━━━━━━

An object 15cm from cancave mirror of focal length 25cm what is the position of the image?If the object is 2cm high . what is the height of the image

Answer»

$\large\bf\underline {To \: find:-}$

$\huge\bf\underline{Solution:-}$

$\bf\underline{\red{Given:-}}$

● object distance (u) = - 15cm

● Focal length (f) = - 25cm

● size of object (h) = 2cm

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$\: \: \: \: \large\underline{ \boxed{ \red{ \bold{ \frac{1}{v} + \frac{1}{u} = \frac{1}{f} }}}}$

➳ 1/v = 1/f - 1/u

➳ 1/v = 1/(-25) -1/(-15)

➳ 1/v = - 1/25 + 1/15

➳ 1/v = (-3 + 5)/75

➳ 1/v = 2/75

➳ 2V = 75

➳ v = 75/2

➳ v = 37.5 cm

And ,

$\red{\bf\:Magnification = h'/h = - v/u}$

⪼ h'/2 = -37.5/-15

⪼ h'/2 = 375/150

⪼ h'/2 = 25/10

⪼ h'/2 = 5/2

⪼ 2H' = 10

⪼ h' = 10/2

⪼ h' = 5cm

Hence,

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