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An object is dropped at a height 500 metre calculate its velocity |
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Answer» Explanation: the distance is ie. s = 500 m Taking u = 0 m because the object is dropped and not thrown and g = 10 m/s^-2 it is along the direction of GRAVITATIONAL acc. Now , APPLYING the values in the eq, s = ut + 1/2 at^2 500 = 0 + 1/2*10*t^2 t=10 s v = final - initial POSITION / final t - initial t = 500/10 m/s =50 m/s
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