1.

An object is dropped from rest at a height of 220m and simultaneously another object is dropped from rest at a height 180m. The difference in their heights after 4s if both the objects drop with same acceleration is

Answer»

Explanation:

Initial DIFFERENCE in height Δh=150m−100m=50m

Distance for each body with TIME is given by: s=ut+

2

1

at

2

In the above question both the object are released from REST, so initial velocity is: u=0

Since the object are dropped at same time, so decrease in height is,

s

1

=s

2

=

2

1

gt

2

=20 m

Height of FIRST body after 2 s, h

1

=150−20=130 m

Height of second body after 2 s, h

2

=100−20=80 m

Difference in heights =50 m


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