An object is placed at 45 cm in front of converging mirror ( CONVEX MI

1.	An object is placed at 45 cm in front of converging mirror ( CONVEX MIRROR ) of radius of curvation 30cm. At what distance the image would be formed. Mention the nature of the image ( BY EXPLANATION )PLEASE DON'T GIVE ANY BAD ANSWERSIF YOU DO IT LIKE THAT I WILL REPORT ANSWER
Answer» Answer: Given, Type of Spherical Mirror = Convex Object Distance (u) = -45 CM [Value taken as negative because object is placed on opposite side of shiny part of convex mirror] Radius of CURVATURE (R) = +30 cm Focal Length (f) = R/2 = +30/2 cm = +15 cm Let's take image distance as v cm. According to equation, = 1/f = 1/v+1/u = 1/15 = 1/v - 1/45 = 1/15 + 1/45 = 1/v = ( 3 + 1 )/45 = 1/v = 4/45 = 1/v = 45/4 cm = v = 11.25 cm = v The Image is formed at 11.25 cm away from the POLE of the mirror. The Image is virtual as the LIGHT rays appear to meet in a convex mirror. The Image is diminished in size like it is in a convex mirror. I hope this helps.

An object is placed at 45 cm in front of converging mirror ( CONVEX MIRROR ) of radius of curvation 30cm. At what distance the image would be formed. Mention the nature of the image ( BY EXPLANATION )PLEASE DON'T GIVE ANY BAD ANSWERSIF YOU DO IT LIKE THAT I WILL REPORT ANSWER

Answer»

Answer:

Given,

Type of Spherical Mirror = Convex

Object Distance (u) = -45 CM

[Value taken as negative because object is placed on opposite side of shiny part of convex mirror]

Radius of CURVATURE (R) = +30 cm

Focal Length (f) = R/2

= +30/2 cm

= +15 cm

Let's take image distance as v cm.

According to equation,

= 1/f = 1/v+1/u

= 1/15 = 1/v - 1/45

= 1/15 + 1/45 = 1/v

= ( 3 + 1 )/45 = 1/v

= 4/45 = 1/v

= 45/4 cm = v

= 11.25 cm = v

The Image is formed at 11.25 cm away from the POLE of the mirror.

The Image is virtual as the LIGHT rays appear to meet in a convex mirror.

The Image is diminished in size like it is in a convex mirror.

I hope this helps.

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