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An object is placed at a distance of 40 cm from aconcave mirror of focal length 15 cm. If the objedctis displaced through a distance of 20 cm towardsthe mirror, the displacement of the image will be |
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Answer» In the initial setup, the object distance is 40 cm, which gives 24 cm image distance given the focal length of 15 cm. (equation: 1/15= 1/40 + 1/i) The second equation changes object distance to 20 cm (40–20), which results in 60 cm as the image distance. (equation: 1/15= 1/20 + 1/i) The difference between 60 and 24 is 36 cm (in the direction away from mirror). |
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