An object is placed at distanceof 15 cm from a diverging mirror of foc

1.	An object is placed at distanceof 15 cm from a diverging mirror of focal lenth 6 cm.find natureand position of the image
Answer» Explanation: Given that u= -15 cm f= 6 cm We NEED to find v We know the formula 1/f = 1/v + 1/u Therefore, 1/v= 1/f – 1/u Substituting the known values in the above EQUATION we get, 1/v= 1/6 + 1/15 1/v = (5+2)/30 (cm) Hence v=30/7 = 4.28cm v= 4.28cm Nature of the image: The image is formed behind the mirror and it is virtual and ERECT.

An object is placed at distanceof 15 cm from a diverging mirror of focal lenth 6 cm.find natureand position of the image

Answer»

Explanation:

Given that

u= -15 cm

f= 6 cm

We NEED to find v

We know the formula

1/f = 1/v + 1/u

Therefore, 1/v= 1/f – 1/u

Substituting the known values in the above EQUATION we get,

1/v= 1/6 + 1/15

1/v = (5+2)/30 (cm)

Hence v=30/7 = 4.28cm

v= 4.28cm

Nature of the image: The image is formed behind the mirror and it is virtual and ERECT.

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An object is placed at distanceof 15 cm from a diverging mirror of focal lenth 6 cm.find natureand position of the image​

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An object is placed at distanceof 15 cm from a diverging mirror of focal lenth 6 cm.find natureand position of the image