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an object is thrown vertically upward and Rises to a height of 10 M calculate 1 the velocity with which the object was thrown upward and second the time taken by the object to reach the highest point |
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Answer» tion:Given,HEIGHT h = 10 cm = 0.1 mAt maximum height, final velocity V = 0Apply SECOND KINEMATIC equationV ² - U² = 2ah 0 - U² = 2 ( - g ) × h U = √2gh = √2 × 10 × 0.1 = √2 m/sApply first kinematic equationV = U + at 0 = U - gtt = U/g = √2 /10 ≅ 0.14 sec Initial velocity is √2 m/s and time required to REACH maximum height is 0.14 sec |
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