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An object is thrown vertically upward with a speed `u_(1)` and it travels 8 m in the last secon of its upward motion. If the object is thrown upward with a speed `u_(2)` which is twice of `u_(1)`, the distance now travelled by the object during the last second of its upward journey will be:A. 32 mB. 16 mC. 12 mD. 8 m |
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Answer» Correct Answer - D The distance travelled in last second is always equal because it is equal to `s = (1)/(2) xx g (t)^(2)` |
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