An object sem in size is placed at 25cm infront of a concave mirror of

1.	An object sem in size is placed at 25cm infront of a concave mirror of focal length 10 cmat what distance from the mirror would aScreen be placed in order to obtain a shortimages find the nature and size of the image.
Answer» Answer: focal length = f = 10 cm object distance = U = 25 cm image distance = V = ? Explanation: Mirror formula, 1/f=1/v+1/u 1/v=1/f+1/u Apply sign convention 1/v=1/f+(-1/u) 1/v=1/f-1/u 1/v=1/10-1/25 1/v=(10-25)/(1025) v=(-15)/(1025) v=-15/250=-3/50 -3/50=-0.06 v=0.06cm At the distance of 0.06 cm from the the mirror , the screen should be placed in order to obtain short image Highly diminished,inverted

An object sem in size is placed at 25cm infront of a concave mirror of focal length 10 cmat what distance from the mirror would aScreen be placed in order to obtain a shortimages find the nature and size of the image.

Answer»

Answer:

focal length = f = 10 cm

object distance = U = 25 cm

image distance = V = ?

Explanation:

Mirror formula,

1/f=1/v+1/u

1/v=1/f+1/u

Apply sign convention

1/v=1/f+(-1/u)

1/v=1/f-1/u

1/v=1/10-1/25

1/v=(10-25)/(10*25)

v=(-15)/(10*25)

v=-15/250=-3/50

-3/50=-0.06

v=0.06cm

At the distance of 0.06 cm from the the mirror , the screen should be placed in order to obtain short image

Highly diminished,inverted

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An object sem in size is placed at 25cm infront of a concave mirror of focal length 10 cmat what distance from the mirror would aScreen be placed in order to obtain a shortimages find the nature and size of the image.​

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An object sem in size is placed at 25cm infront of a concave mirror of focal length 10 cmat what distance from the mirror would aScreen be placed in order to obtain a shortimages find the nature and size of the image.