An object travels 25 M in 5 Sec and then object travels 25 M in 3 Sec.

1.	An object travels 25 M in 5 Sec and then object travels 25 M in 3 Sec. What is theaverage speed of the object?
Answer» $\mathfrak{\large{\underline{\underline{Given:-}}}}$ In 1 st case :- Distance travelled = 25 m Time taken = 5 sec In 2 ND case :- Distance travelled = 25 m Time taken = 3 sec $\mathfrak{\large{\underline{\underline{To find:-}}}}$ Average speed of OBJECT = ? $\mathfrak{\large{\underline{\underline{Solution:-}}}}$ ★ $\boxed{\sf{Average speed = \frac{total \: distance \: travelled}{total \: time \: taken} }}$ $\implies$ $\bold{ = \frac{<klux>25</klux> + 25}{5 + 3} }$ $\implies$ $\bold{= \frac{100}{8} m /sec}$ $\implies$ $\bold{ = \frac{25}{2} m/sec}$ hence , average speed = $\ \frac{25}{2} m/sec$