InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
An old piece of wood has 25.6T as much `C^(14)` as ordinary wood today has. Find the age of the wood. Half-life period of `C^(14)` is 5760 years. |
|
Answer» Suppose the amount of `C^(14)` present in the wood originally (i.e., the same which the wood today has) `= a`. Then the amount of `C^(14)` present now in the old wood `(25.6)/(100) a = 256a` The time `t` in which `C^(14)` changed from `a` to `0.256a` will then be given by `t = (2.303)/(K) "log" (a)/(0.256a)` But `K = (0.693)/(t_(1//1)) = (0.693)/(5760) = 1.203 xx 10^(-4) "year"^(-1)` `:. t = (2.303)/(1.203 xx 10^(-4)) "log" (1)/(0.256) = 11329` years |
|