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The number of `alpha and beta-`particles emitted in the nuclear reaction `._(90)Th^(228) rarr ._(83)Bi^(212)` are respectivelyA. 4 , 1B. 3 , 7C. 8, 1D. 4, 7 |
Answer» Correct Answer - A `._(90)Th^(228)rarr ._(83)Bi^(212)` No. of `alpha-"particle" = (228 - 212)/(4) = (16)//(4) = 4` No. of `beta-"particle" = 2xx 4 - 90 + 83` |
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