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After np orbitals are filled, the next orbital filled will be :-(a). `(n+1)s`(b). `(n+2)p`(c). `(n+1)d`(d). `(n+2)s`A. `(n+1) s`B. `(n+2)p`C. `(n+1) d`D. `(n+2) s`

Answer» Correct Answer - A
Total number of electrons in an orbital `=2(2l+1)`
The value of `l` varies from `0` to `n-1` :. Total numbers of electrons in any orbit `=sum_(l=0)^(l=n-1) 2(2l+1)`.


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