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During the transformation of `._(c )X^(a)` to `._(d)Y^(b)` the number of `beta`-particles emitted are a. `d + ((a - b)/(2)) - c` b. `(a - b)/(c )` c. `d + ((a - b)/(2)) + c` d. `2c - d + a = b`A. a. `d + ((a - b)/(2)) - c`B. b. `(a - b)/(c )`C. c. `d + ((a - b)/(2)) + c`D. d. `2c - d + a = b` |
Answer» Correct Answer - a. `d + ((a - b)/(2)) - c` a. For transformation of `._(c )X^(a) rarr ._(d)Y^(b) + x_(2)He^(4) + beta` Number of `alpha`-particles emitted `= (a - b)/(4)` Equating for atomic number on both sides, we get `c = d + 2 ((a - b)/(2)) + beta (-1)` or `beta = d + (a - b)/(2) - c` |
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