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    				| 1. | An open organ pipe has a fundamental frequency of `300 H_(Z)` . The first overtone of a closed organ pipe has the same frequency as the first overtone of this open pipe . How long is each pipe ? (Speed of sound in air = `330 m//s`) | 
| Answer» Correct Answer - C Fundamental freqency of an open organ pipe, `f_(1)= (nu)/(2l_(0)) rArr l_(0) = (nu)/(2f_(1)) = (330)/(2xx300)` = `0.55m` = `55 cm` Given, first overtone of closed organ pipe = first overtone of open organ pipe Hence, `3((nu)/(4l_(C))) = 2((nu)/(2l_(0)))` `:. l_(C) = (3)/(4) l_(0) = ((3)/(4)) (0.55)` = `0.4125 m` = `41. 25 cm` | |