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An open organ pipe of length is 50 cm, if the velocity of sound in air is 320m/s , then the frequency of its fundamental note will beA. 160HzB. 480HzC. 320HzD. 640Hz |
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Answer» Correct Answer - C `n=(v)/(2l) = (320)/(50xx2xx10^(-2))-320Hz` |
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