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An organ pipe is closed at one end has fundamental frequency of 1500 Hz. The maximum number of overtones generated by this pipe which a normal person can hear isA. `14`B. `13`C. `6`D. `9` |
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Answer» Correct Answer - C Critical hearing frequency in Nth mode then frequency of vibration `n=((2N-1)v)/(4l)=(2N-1)n_1` (where `n_1=`fundamental frequency of vibration) Hence `20,00=(2N-1)xx1500impliesN=7.1=7` Also, in closed pipe Number of over tones`=`(No. of mode of vibration)`-1=7-1=6`. |
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