1.

An organ pipe of length 0.4m is open at both ends . The speed of sound in air is `340ms^(-1)` . The fundamental frequency isA. 400HzB. 425HzC. 450HzD. 475Hz

Answer» Correct Answer - B
`n=(v)/(4l) = (340)/(4xx0.4)`
`=3400/8 = 425Hz`


Discussion

No Comment Found

Related InterviewSolutions