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An organ pipe of length `L` is open at one end and closed at other end. The wavelengths of the three lowest resonating frequencies that can be produced by this pipe areA. 4L,2L,LB. 2L,L,L/2C. 2L,L,2L/3D. 4L,4L/3,4L/5 |
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Answer» Correct Answer - D `L=(2n-1) (lambda)/4` `lambda=(4L)/((2n-1)), lambda_(1)=(4L)/(2(1)-1)=4L` `lambda_(2)=(4L)/(4-1) =(4L)/3` , `lambda_(3)=(4L)/(6-1) =(4L)/5` |
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