1.

An organic compound P when heated with excess concentrated H_(2)SO_(4) at 443 K produced compound Q. The number of carbon atoms in P and Q are same. Compound Q when treated with hydrogen in presence of nickel or palladium formed compound R. One mole of 'R' when reacts with sufficient O_(2) given two moles of carbon dioxide and three moles of water. Identify the compounds P, Q and R. Write chmical equations for the reactions.

Answer»

Solution :`P:C_(2)H_(5)` (Ethanol)
`Q:H_(2)C=CH_(2)` (Ethene)
`R:H_(3)C-CH_(3)` (Ethane)
Chemical REACTIONS :
`underset("Ethanol (P)")(C_(2)H_(5)OH)OVERSET("Concentrated "H_(2)SO_(4))underset(443 K)tounderset("Ethene")(H_(2)C)=underset((Q))(CH_(2))+H_(2)O`
`underset("Ethene (Q)")(H_(2)C=CH_(2))+H_(2)overset(Ni//Pd)to underset("Ethane (R)")(H_(3)C-CH_(3))`
`underset("Ethane ( R )")(C_(2)H_(6))+(7)/(2)O_(2)to2CO_(2)(g)+3H_(2)O(1)`


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