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An organic compound P when heated with excess concentrated H_(2)SO_(4) at 443 K produced compound Q. The number of carbon atoms in P and Q are same. Compound Q when treated with hydrogen in presence of nickel or palladium formed compound R. One mole of 'R' when reacts with sufficient O_(2) given two moles of carbon dioxide and three moles of water. Identify the compounds P, Q and R. Write chmical equations for the reactions. |
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Answer» Solution :`P:C_(2)H_(5)` (Ethanol) `Q:H_(2)C=CH_(2)` (Ethene) `R:H_(3)C-CH_(3)` (Ethane) Chemical REACTIONS : `underset("Ethanol (P)")(C_(2)H_(5)OH)OVERSET("Concentrated "H_(2)SO_(4))underset(443 K)tounderset("Ethene")(H_(2)C)=underset((Q))(CH_(2))+H_(2)O` `underset("Ethene (Q)")(H_(2)C=CH_(2))+H_(2)overset(Ni//Pd)to underset("Ethane (R)")(H_(3)C-CH_(3))` `underset("Ethane ( R )")(C_(2)H_(6))+(7)/(2)O_(2)to2CO_(2)(g)+3H_(2)O(1)` |
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