An organic compound undergoes first decompoistion. The time taken for its decompoistion to `1//8` and `1//10` of its initial concentration are `t_(1//8)` and `t_(1//10)`, respectively. What is the value of `([t_(1//8)])/([t_(1//10)]) xx 10`? `(log_(10)2 = 0.3)`A. 2B. 3C. 3D. 9

An organic compound undergoes first decompoistion. The time taken for

1.	An organic compound undergoes first decompoistion. The time taken for its decompoistion to `1//8` and `1//10` of its initial concentration are `t_(1//8)` and `t_(1//10)`, respectively. What is the value of `([t_(1//8)])/([t_(1//10)]) xx 10`? `(log_(10)2 = 0.3)`A. 2B. 3C. 3D. 9
Answer» Correct Answer - D For a first order process, `kt="In[A]_(0)/([A])` `rArrkt_(1//8)=In[A]_(0)/([A]_(0)//8)="In "8` `and" "kt_(1//10)="In"[A]_(0)/([A]_(0)//10)="In "10` …..(ii) Therefore, " `(t_(1//8))/(t_(1//8))= ("In 8")/("In 10")=log8 = 3 log 2 = 3 xx 0.3= 0.9 ` ` rArr " "t_(1//8)/t_(1//10)xx 10 xx 0.9 xx 10 = 9.0 `

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An organic compound undergoes first decompoistion. The time taken for its decompoistion to `1//8` and `1//10` of its initial concentration are `t_(1//8)` and `t_(1//10)`, respectively. What is the value of `([t_(1//8)])/([t_(1//10)]) xx 10`? `(log_(10)2 = 0.3)`A. 2B. 3C. 3D. 9

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