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An ultrasound signal of frequency 50 kHz is sent vertically into sea water. The signal gets reflected from the ocean bed and returns to the surface 0.80 s after it was emitted. The speed of sound in sea water is `1500ms^-1`. a. Find the depth of the sea. b. What is the wavelength of this signal in water. |
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Answer» a. Let the depth of the sea be d. the total distance travelled by the sigN/Al is 2d. By the question, `2d=(1500ms^-1)(0.8s)=1200m` or `d=600m` b. using the equation `v=vlamda` `lamda=v/v=(1500ms^1)/(50xx10^3s^-1)=3.0cm` |
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