An uranium 92U235 fission reaction produces 216Mev .the amount of uran

1.	An uranium 92U235 fission reaction produces 216Mev .the amount of uranium required to run a 100Mw nuclear power plant for a day with 100%efficiency is.
Answer» If a URANIUM 92U235 FISSION reaction produces 216MeV, the amount of uranium required to run a 100MW nuclear power plant for a day with 100% efficiency is given as- 1. Let 92U235 be represented by U. 2. We know that, 1eV= 8.8910^-9 Wsec => 216MeV = 21610^6eV = 21610^6 8.8910^-9 Wsec= 1.94Wsec 3. For 1 day, the energy produced by one reaction would be 1.94/86400 = 2.2441810^-5 4. Thus the amount of U required to run the 100MW = 108W plant = 2.2441810^-5/108 = 4.4559710^12.

An uranium 92U235 fission reaction produces 216Mev .the amount of uranium required to run a 100Mw nuclear power plant for a day with 100%efficiency is.

Answer»

If a URANIUM 92U235 FISSION reaction produces 216MeV, the amount of uranium required to run a 100MW nuclear power plant for a day with 100% efficiency is given as-

1. Let 92U235 be represented by U.

2. We know that, 1eV= 8.89*10^-9 Wsec

=> 216MeV = 216*10^6eV

= 216*10^6 * 8.89*10^-9 Wsec= 1.94Wsec

3. For 1 day, the energy produced by one reaction would be

1.94/86400 = 2.24418*10^-5

4. Thus the amount of U required to run the 100MW = 10*8W plant

= 2.24418*10^-5/10*8 = 4.45597*10^12.

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An uranium 92U235 fission reaction produces 216Mev .the amount of uranium required to run a 100Mw nuclear power plant for a day with 100%efficiency is.​

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An uranium 92U235 fission reaction produces 216Mev .the amount of uranium required to run a 100Mw nuclear power plant for a day with 100%efficiency is.