Anautomobiletravellingwithauniformspeedof60km/honapplyingthebrakescome

1.	Anautomobiletravellingwithauniformspeedof60km/honapplyingthebrakescomestoastopatadistanceof20mwithuniformretardation.Ifthecardoublesitsinitialspeed,whatwillbethe new stoppingdistance?
Answer» Answer: Given, INITIAL VELOCITY (u) = 60 km/hr Final Velocity (v) = 0 km/hr Distance TRAVELLED (S) = 20 m = 0.02 km Retardation (a) = v² = u² - 2aS = 0 = (60)² - [2a0.02] = 0.04a = 3600 = a = 90000 km/hr² Now, Initial Velocity (u) = 120 km/hr Final Velocity (v) = 0 km/hr Retardation (a) = 90000 km/hr² Here, we are assuming that the car retards at the same rate LIKE the last time. = v² = u² - 2aS = 0 = (120)² - [290000S] = 180000S = 14400 = S = 0.008 km or, = S = 8 m Answer: Assuming that the car retards at the same rate, it'll travel upto 0.008 km or 8 m. I hope this helps.

Anautomobiletravellingwithauniformspeedof60km/honapplyingthebrakescomestoastopatadistanceof20mwithuniformretardation.Ifthecardoublesitsinitialspeed,whatwillbethe new stoppingdistance?

Answer»

Answer:

Given,

INITIAL VELOCITY (u) = 60 km/hr

Final Velocity (v) = 0 km/hr

Distance TRAVELLED (S) = 20 m

= 0.02 km

Retardation (a) = v² = u² - 2aS

= 0 = (60)² - [2*a*0.02]

= 0.04a = 3600

= a = 90000 km/hr²

Now,

Initial Velocity (u) = 120 km/hr

Final Velocity (v) = 0 km/hr

Retardation (a) = 90000 km/hr²

Here, we are assuming that the car retards at the same rate LIKE the last time.

= v² = u² - 2aS

= 0 = (120)² - [2*90000*S]

= 180000S = 14400

= S = 0.008 km

or,

= S = 8 m

Answer: Assuming that the car retards at the same rate, it'll travel upto 0.008 km or 8 m.

I hope this helps.

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