Anhydrous AlCl_(3) is covalent. From the data given below, predict whether it would remain covalent or become ionic in aqueous solution. Delta_(i)H(AlCl_(3))=5137kJmol^(-1), Delta_("hyd")H(Al^(3+))=-4665kJmol^(-1) Delta_("hyd")H(Cl^(-))=-381kJmol^(-1).

Anhydrous AlCl_(3) is covalent. From the data given below, predict whe

1.	Anhydrous AlCl_(3) is covalent. From the data given below, predict whether it would remain covalent or become ionic in aqueous solution. Delta_(i)H(AlCl_(3))=5137kJmol^(-1), Delta_("hyd")H(Al^(3+))=-4665kJmol^(-1) Delta_("hyd")H(Cl^(-))=-381kJmol^(-1).
Answer» Solution :Total energy released `=1Delta_("HYD")H(Al^(3+))+3Delta_("hyd")H(Cl^(-))` `=[(-4665)+(3xx-381)]kJmol^(-1)=-5808kJmol^(-1)` Total energy REQUIRED `=Delta_(i)H(AlCl_(3))=5137kJmol^(-1)` Since energy released is greater than the energy required, the compound will ionize in aqueous solution.