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Answer»

Answer:

The magnitude of force = 10⁻⁴ N

Explanation:

Correct Question : A force acts for 10 s on a body of mass 10⁻² kg initially at rest after which the force ceases come to an end to act. The body travels 0.5 m in the next 5 s. Find the magnitude of the force.

Let the body starts from rest.

∴ u = 0

Final velocity = distance / time

⇒ Final velocity = 0.5/5 = 0.1 m/s

⇒ Final Velocity = = 0.1 m/s

V = u + at

⇒ a = (v-u)/t

Here,

  • v = 0.1 m/s
  • u = 0 m/s
  • t = 10 s

∴ a = (0.1 - 0)/10

⇒ a = 0.1/10

⇒ a = 0.01 m/s²

Force(F) = Mass(m) × Acceleration(a)

Here,

  • Mass = 10⁻² kg = 1/100 kg = 0.01 kg
  • Acceleration = 0.01 m/s²

∴ F = 0.01 × 0.01

⇒ F = 0.0001 N

⇒ F = 10⁻⁴ N


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