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Ans: 6058. Two tall buildings are at a distance 180m and facing each other. With what velocity must aball be thrown horizontally from a window 55m above the ground in one building, so that itenters a window 10m above the ground in the second building?(Take, g 10 m/s)[Ans: 60m/s][Hints: Equation of trajectory is, y (22u2 |
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Answer» Height = h= 55-10= 45Distance= s= 180 mtime taken = tso, h=1/2 gt²or t=√2h/g√2 x 45/9.8=√90/9.8=√9 = 3S= velocity x t180= velocity x 3velocity =180/3 = 60 m/s |
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