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`ArarrB, DeltaH= -10 KJ mol^(-1), E_(a(f))=50 KJ mol^(-1)`, then `E_(a)` of `BrarrA` will beA. `40 KJ mol^(-1)`B. `50 KJ mol^(-1)`C. `-50 KJ mol^(-1)`D. `60 KJ mol^(-1)` |
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Answer» Correct Answer - D `A rarr B, DeltaH = -10 KJ mol^(-1)` It is an exothermic reaction. `E_(a(b))=E_(a(f))-(DeltaH)` `=50 -(-10)` `=60 KJ` |
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