1.

`ArarrB, DeltaH= -10 KJ mol^(-1), E_(a(f))=50 KJ mol^(-1)`, then `E_(a)` of `BrarrA` will beA. `40 KJ mol^(-1)`B. `50 KJ mol^(-1)`C. `-50 KJ mol^(-1)`D. `60 KJ mol^(-1)`

Answer» Correct Answer - D
`A rarr B, DeltaH = -10 KJ mol^(-1)`
It is an exothermic reaction.
`E_(a(b))=E_(a(f))-(DeltaH)`
`=50 -(-10)`
`=60 KJ`


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