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Areas of two similar triangles are 225 sq cm and 81 sq cm. If a side of the smaller triangle is 12 cm, then find the corresponding side of the bigger triangle. |
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Answer» Let the areas of two similar triangles be `A_(1)` and `A_(2)`. Let their respective corresponding sides be `s_(1)` and `s_(2)`. `A_(1)=225sqcm, A_(2)=81` sq. cm and `s_(2)=12cm`………….(Given) The two triangles are similar. `:.` by the theorem of areas of similar triangles, `:.(A_(1))/(A_(2))=(s_(1)^(2))/(s_(2)^(2))` `:.225/81=(s_(1)^(2))/(12^(2))` `:.s_(1)^(2)=(225xx12^(2))/81` `:.s_(1)=(15xx12)/9` .................(Taking square roots on both the sides) `:.s_(1)=20` cm The corresponding side of the bigger triangle is 20 cm. |
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