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As per Bohr model , the minimum energy (in eV) required to remove electron from the ground state of doubly ioinized `Li` alom `(Z = 3)` is |
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Answer» Correct Answer - D For hydrogen and hydrogen like atoms, `E_n = -13.6((Z)^2)/((n^2)))` Therefore, ground state energy of doubly ionized lithium atom (Z =3, n =1) will be `E_1 = (-13.6) ((3)^2/((1))^2` =- 122.4 eV `:.` lonization energy of an electron in ground state of doubly ionized lithium atom will be 122.4 eV. |
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