Assume that the growth of bacteria follows first order kinetics with a rate constant of 2/s. If the initial population of the bacteria is 2000, then the population of it after 30s will be _____(a) 2 × 10^29(b) 4 × 10^29(c) 2 × 10^30(d) 8 × 10^29This question was posed to me in an online interview.My question is based upon Biological Classification in division Biological Classification of Biology – Class 11

Assume that the growth of bacteria follows first order kinetics with a

1.	Assume that the growth of bacteria follows first order kinetics with a rate constant of 2/s. If the initial population of the bacteria is 2000, then the population of it after 30s will be _____(a) 2 × 10^29(b) 4 × 10^29(c) 2 × 10^30(d) 8 × 10^29This question was posed to me in an online interview.My question is based upon Biological Classification in division Biological Classification of Biology – Class 11
Answer» Right ANSWER is (a) 2 × 10^29 To ELABORATE: n = N×e^kt = N×10^kt/2.303 Where, n = current population N = initial population k = RATE constant t = TIME taken n = 2000×10^2×30/2.303 = 2×10^29.

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