1.

At 1 atm pressure, `DeltaS=75JK^(-1)mol^(-1),DeltaH=30kJ" "mol^(-1)`, the temperature of the reaction at equilibrium isA. 400 KB. 330 KC. 200 KD. 110 K

Answer» Correct Answer - A
`DeltaG=DeltaH-TDeltaS`
At equilibrium, `DeltaG=0`
`T=(DeltaH)/(DeltaS)=(30xx10^(3))/(75)=400K`


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