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The free energy for a reaction having `DeltaH=31400cal,DeltaS=32" cal "K^(-1)mol^(-1)` at `1000^(@)C` isA. `-9336cal`B. `-7386cal`C. `-1936cal`D. `+9336cal` |
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Answer» Correct Answer - A From Gibbs-Helmholtz equation, we know `DeltaG=DeltaH-T*DeltaS=31400-1273xx32` `=31400-40736=-9336cal` |
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