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For the reaction `AtoB,DeltaH=+23kJ//mol and BtoC,DeltaH=-18kJ//mol`, the decreasing order of enthalpy of A,B,C follows the orderA. A,B,CB. B,C,AC. C,B,AD. C,A,B |
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Answer» Correct Answer - B `A to B,DeltaH=+24" kJ "mol^(-1)` `H_(B)-H_(A)=+24`. . .. (i) `B to C, DeltaH=18" kJ "mol^(-1)` `H_(C)-H_(B)=-18` . . (ii) `H_(B)-H_(C)=+18` . . (iii) `H_(C)-H_(A)=6` (from (i) and (ii)) `H_(B) gt H_(C) gt H_(A)`. |
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